Abstract
The neutron-rich nucleus 13B was studied via the proton transfer reaction 4He(12Be, 13Bγ) at 50 A MeV. The known 4.83-MeV excited state was strongly populated and its spin and parity were assigned to 1 / 2+ by comparing the angular differential cross section data with DWBA calculations. This low-lying 1 / 2+ state is interpreted as a proton intruder state and indicates a deformation of the nucleus.
Original language | English |
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Pages (from-to) | 311-314 |
Number of pages | 4 |
Journal | Physics Letters, Section B: Nuclear, Elementary Particle and High-Energy Physics |
Volume | 666 |
Issue number | 4 |
DOIs | |
Publication status | Published - 2008 Sept 4 |
Keywords
- He(Be, Bγ)
- Intruder state
- Proton single particle state
- Proton transfer reaction
ASJC Scopus subject areas
- Nuclear and High Energy Physics